Loading...

Loading, please wait...

Back to Topics

Control Systems
Time Response Analysis

Practice questions from Time Response Analysis.

54
Total
0
Attempted
0%
0
Correct
0%
0
Incorrect
0%
Q#1 Time Response Analysis GATE EE 2024 (Set 1) MCQ +1 mark -0.33 marks

Consider the standard second-order system of the form  with the poles  and  having negative real parts. The pole locations are also shown in the figure. Now consider two such second-order systems as defined below:

System 1:  and

System 2:  and

Which one of the following statements is correct?

Settling time of System 1 is more than that of System 2.

Settling time of System 2 is more than that of System 1.

Settling times of both the systems are the same.

Settling time cannot be computed from the given information.

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#2 Time Response Analysis GATE EE 2024 (Set 1) MCQ +1 mark -0.33 marks

Consider the cascaded system as shown in the figure. Neglecting the faster component of the transient response, which one of the following options is a first order pole-only approximation such that the steady-state values of the unit step responses of the original and the approximated systems are same?

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#3 Time Response Analysis GATE EE 2022 (Set 1) MCQ +2 marks -0.66 marks

The damping ratio and undamped natural frequency of a closed loop system as shown in the figure, are denoted as  and ωn, respectively. The values of  and  are

 = 0.5 and  = 10 rad/s

 = 0.1 and  = 10 rad/s

 = 0.707 and  = 10 rad/s

 = 0.707 and  = 100 rad/s

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#4 Time Response Analysis GATE EE 2020 (Set 1) MCQ +2 marks -0.66 marks

Consider a permanent magnet dc (PMDC) motor which is initially at rest. At t = 0, a dc voltage of 5 V is applied to the motor. Its speed monotonically increases from 0 rad/s to 6.32 rad/s in 0.5 s and finally settles to 10 rad/s. Assuming that the armature inductance of the motor is negligible, the transfer function for the motor is

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#5 Time Response Analysis GATE EE 2019 (Set 1) MCQ +1 mark -0.33 marks

The output response of a system is denoted as y(t), and its Laplace transform is given by   the steady state value of y(t)  is

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#6 Time Response Analysis GATE EE 2018 (Set 1) NAT +1 mark -0 marks

Consider a unity feedback system with forward transfer function given by

 

The steady-state error in the output of the system for a unit-step input is______(up to 2 decimal places).

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#7 Time Response Analysis GATE EE 2018 (Set 1) MCQ +1 mark -0.33 marks

Match the transfer functions of the second-order systems with the nature of the systems given below.

Transfer functions 

Nature of system 

P.

I. Over damped

Q.

II. Critically damped

R.

III. Under damped

P-I, Q-II, R-III

P-II, Q-I, R-III

P-III, Q-II, R-I

P-III, Q-I, R-II

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#8 Time Response Analysis GATE EE 2018 (Set 1) NAT +2 marks -0 marks

The unit step response y(t) of a unity feedback system with open loop transfer function is shown in the figure.

Untitled-18.png

The value of K is ________ (up to decimal places).

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#9 Time Response Analysis GATE EE 2017 (Set 1) NAT +2 marks -0 marks

For a system having transfer function, a unit step input is applied at time t= 0.  The value of the response of the system at t = 1.5 sec. (rounded off to three decimal places) is

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#10 Time Response Analysis GATE EE 2017 (Set 2) MCQ +1 mark -0.33 marks

When a unit ramp input is applied to the unity feedback system having closed loop transfer function , the steady rate error will be

0

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#11 Time Response Analysis GATE EE 2017 (Set 2) MCQ +2 marks -0.66 marks

Which of the following systems has maximum peak overshoot due to a unit step input?

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#12 Time Response Analysis GATE EE 2016 (Set 2) MCQ +2 marks -0.66 marks

A second-order real system has the following properties: 

(a) the damping ratio  and undamped natural frequency ,

(b) the steady state value of the output, to a unit step input, is 1.02

The transfer function of the system is

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#13 Time Response Analysis GATE EE 2015 (Set 2) NAT +1 mark -0 marks

An open loop control system results in a response of  for a unit impulse input. The DC gain of the control system is ___________.

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#14 Time Response Analysis GATE EE 2015 (Set 2) MCQ +2 marks -0.66 marks

The unit step response of a system with the transfer function  is given by which one of the following waveforms?

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#15 Time Response Analysis GATE EE 2014 (Set 2) NAT +1 mark -0 marks

The closed-loop transfer function of a system is . The steady state error due to unit step input is_____________.

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#16 Time Response Analysis GATE EE 2013 (Set 1) MCQ +1 mark -0.33 marks

Assuming zero initial condition, the response y(t) of the system given below to a unit step input u(t) is         

u(t)

t u(t)

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#17 Time Response Analysis GATE EE 2013 (Set 1) MCQ +2 marks -0.66 marks

The open-loop transfer function of a dc motor is given as. When connected in feedback as shown below, the approximate value of  that will reduce the time constant of the closed loop system by one hundred times as compared to that of the open-loop system is

1

5

10

100

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#18 Time Response Analysis GATE EE 2011 (Set 1) MCQ +1 mark -0.33 marks

The steady state error of a unity feedback linear system for a unit step input is 0.1. The steady state error of the same system, for a pulse input r(t) having a magnitude of 10 and a duration of one second, as shown in the figure is         

7.jpg

0

0.1

1

10

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#19 Time Response Analysis GATE EE 2010 (Set 1) MCQ +1 mark -0.33 marks

For the system , the approximate time taken for a step response to reach 98% of its final value is

1 s

2 s

4 s

8 s

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#20 Time Response Analysis GATE EE 2009 (Set 1) MCQ +2 marks -0.66 marks

The unit-step response of a unity feedback system with open loop transfer function  is shown in the figure.  The value of K is

Q27.jpg

0.5

2

4

6

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#21 Time Response Analysis GATE EE 2008 (Set 1) MCQ +2 marks -0.66 marks

The transfer function of a linear time invariant system is given as

The steady state value of the output of this system for a unit impulse input applied at time instant t = 1 will be

0

0.5

1

2

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#22 Time Response Analysis GATE EE 2008 (Set 1) MCQ +2 marks -0.66 marks

The transfer function of a system is given as         

This system is        

An over damped system

An under damped system

A critically damped system

An unstable system

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#23 Time Response Analysis GATE EE 2007 (Set 1) MCQ +2 marks -0.66 marks

Consider the feedback control system shown below which is subjected to a unit step input. The system is stable and has the following parameters and         

The steady state value of z is

1

0.25

0.1

0

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#24 Time Response Analysis GATE EE 2007 (Set 1) MCQ +2 marks -0.66 marks

Consider the R-L-C circuit shown in figure.

Q80.jpg

For a step-input, the overshoot in the output will be

0, since the system is not under-damped

5%

16%

48%

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#25 Time Response Analysis GATE EE 2007 (Set 1) MCQ +2 marks -0.66 marks

Consider the R-L-C circuit shown in figure.

Q80.jpg

If the above step response is to be observed on a non-storage CRO, then it would be best to have the , as a

Step function

Square wave of frequency 50 Hz

Square wave of frequency 300 Hz

Square wave of frequency 2.0 kHz

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#26 Time Response Analysis GATE EE 2005 (Set 1) MCQ +2 marks -0.66 marks

When subjected to a unit step input, the closed loop control system shown in Figure will have a steady state error of

-1.0

-0.5

0

0.5

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#27 Time Response Analysis GATE EE 2004 (Set 1) MCQ +1 mark -0.33 marks

Consider the function , where F(s) is the Laplace transform of the function f(t). The initial value of f(t) is equal to

5

0

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#28 Time Response Analysis GATE EE 2004 (Set 1) MCQ +2 marks -0.66 marks

The block diagram of a closed loop control system is given by figure. The values of K and P such that the system has a damping ratio of 0.7 and an un-damped natural frequency  of 5rad/sec, are respectively equal to                 

Q74.jpg

20 and 0.3

20 and 0.2

25 and 0.3

25 and 0.2

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#29 Time Response Analysis GATE EE 2004 (Set 1) MCQ +2 marks -0.66 marks

The unit impulse response of a second order under-damped system starting from rest is given by

The steady-state value of the unit step response of the system is equal to

0

0.25

0.5

1.0

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#30 Time Response Analysis GATE EE 2003 (Set 1) MCQ +1 mark -0.33 marks

A control system is defined by the following mathematical relationship

The response of the system as t →∞ is

x = 6

x = 2

x = 2.4

x = −2

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#31 Time Response Analysis GATE EE 2003 (Set 1) MCQ +2 marks -0.66 marks

A control system with certain excitation is governed by the following mathematical equation         

The natural time constants of the response of the system are

2s and 5s

3s and 6s

4s and 5s

1/3s and 1/6s

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#32 Time Response Analysis GATE EE 2003 (Set 1) MCQ +2 marks -0.66 marks

The block diagram shown in Figure gives a unity feedback closed loop control system. The steady state error in the response of the above system to unit step input is

25%

0.75%

6%

33%

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#33 Time Response Analysis GATE EE 2003 (Set 1) MCQ +2 marks -0.66 marks

The roots of the closed loop characteristic equation of the system shown in above figure are

−1 and −15

6 and 10

−4 and −15

−6 and −10

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#34 Time Response Analysis GATE EE 2001 (Set 1) MCQ +2 marks -0.66 marks

Given the relationship between the input u(t) and the output y(t) to be, the transfer function  is

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#35 Time Response Analysis GATE EE 2000 (Set 1) MCQ +1 mark -0.33 marks

A unity feedback system has open loop transfer function G(s). The steady-state error is zero for

Step input and type-1 G(s)

Ramp input and type – 1 G(s)

Step input and type-0 G(s)

Ramp input and type – 0 G(s)

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#36 Time Response Analysis GATE EE 2000 (Set 1) MCQ +1 mark -0.33 marks

A linear time-invariant system initially at rest, when subjected to a unit-step input, gives a response,. The transfer function of the system is:

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#37 Time Response Analysis GATE EE 2000 (Set 1) MCQ +2 marks -0.66 marks

A unity feedback system has open loop transfer function. The peak overshoot in the step-input response of the system is approximately equal to:

5%

10%

15%

20%

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#38 Time Response Analysis GATE EE 1998 (Set 1) MCQ +1 mark -0.33 marks

The output of a linear time invariant control system is c(t) for a certain input r(t). If r(t) modified by passing it through a block whose transfer function is  and then applied to the system, the modified output of the system would be

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#39 Time Response Analysis GATE EE 1998 (Set 1) MCQ +2 marks -0.66 marks

The Laplace transform of  is:

None of the above

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#40 Time Response Analysis GATE EE 1997 (Set 1) NAT +2 marks -0 marks

A first order system is initially at rest and excited by a step input at time t=0. Its output becomes 1.1V is in 4 seconds and eventually reacts a steady state value of 2V. Determine its time constant

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#41 Time Response Analysis GATE EE 1996 (Set 1) MCQ +1 mark -0.33 marks

The unit-impulse response of a unit-feedback control system is given by

The open loop transfer function is equal to

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#42 Time Response Analysis GATE EE 1996 (Set 1) MCQ +1 mark -0.33 marks

Consider the unit-step response of a unity-feedback control system whose open-loop transfer functions is . The maximum overshoot is equal to

0.143

0.153

0.163

0.173

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#43 Time Response Analysis GATE EE 1996 (Set 1) MCQ +1 mark -0.33 marks

For a feedback control system of type 2, the steady state error for a ramp input is

infinite

constant

zero

Indeterminate

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#44 Time Response Analysis GATE EE 1996 (Set 1) MCQ +2 marks -0.66 marks

For the system shown in figure, with a damping ratio  of 0.7 and an undamped natural frequency

 of 4 rad/sec, the values of K and a are         

Q 2_1

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#45 Time Response Analysis GATE EE 1996 (Set 1) MCQ +2 marks -0.66 marks

The unit impulse response of a system is given as . The step response of the same system for  is equal to

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#46 Time Response Analysis GATE EE 1995 (Set 1) MCQ +1 mark -0.33 marks

The impulse response of an initially relaxed linear system is . To produce a response of , the input must be equal to         

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#47 Time Response Analysis GATE EE 1995 (Set 1) MCQ +1 mark -0.33 marks

The closed loop transfer function of a control system is given by

For a unit step input the output is

zero

infinity

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#48 Time Response Analysis GATE EE 1995 (Set 1) MCQ +1 mark -0.33 marks

The Laplace transform of f(t) is F(s). Given , the final value of f(t) is :

infinity

zero

one

none of the above

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#49 Time Response Analysis GATE EE 1995 (Set 1) NAT +1 mark -0 marks

The steady state error due to a step input for type 1 system is _______________

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#50 Time Response Analysis GATE EE 1995 (Set 1) NAT +2 marks -0 marks

Root locations of the characteristic unit step responses of second order of second equations order systems        

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#51 Time Response Analysis GATE EE 1994 (Set 1) NAT +1 mark -0 marks

If f(t) is the step-response of a linear-time invariant system, then its impulse response is given by .
(True=1, False=0)

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#52 Time Response Analysis GATE EE 1992 (Set 1) MCQ +1 mark -0.33 marks

For what values of ‘a’ does the system shown in figure have a zero steady state error  for a step input?                 

Z:\PY\EE\Redreaw figure\control system\update\266-02.jpg

a=10

for no value of ‘a’

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#53 Time Response Analysis GATE EE 1992 (Set 1) MCQ +2 marks -0.66 marks

Match the following transfer functions and impulse responses

Transfer functions        

(a)

(b)

Z:\PY\EE\Redreaw figure\control system\update\266-03-(b).jpg

(c)

Z:\PY\EE\Redreaw figure\control system\update\266-03-(b).jpg

(d)

(a) => (Q)
(b) => (P)
(c) => (S)
(d) => (R)

(a) => (Q)
(b) => (S)
(c) => (P)
(d) => (R)

(a) => (R)
(b) => (P)
(c) => (S)
(d) => (Q)

(a) => (P)
(b) => (Q)
(c) => (S)
(d) => (R)

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock
Q#54 Time Response Analysis GATE EE 1991 (Set 1) MSQ +1 mark -0 marks

A first order system and its response to a unit step input are shown in figure. The system parameters are

a= _______________

K= _______________

Z:\PY\EE\Redreaw figure\control system\update\266-01.jpg

a=5

k=10

a=10

k=5

Explanation Locked!

Unlock this branch to view the explanation, track, bookmark and more.

Sign in to Unlock