In the figure shown, all elements used are ideal. For time t < 0, \(S_1\) remained closed and \(S_2\) open. At
t = 0, \(S_1\) is opened and \(S_2\) is closed.  If the voltage \(Vc_2\) across the capacitor \(C_2\) at t = 0 is zero, the voltage across the capacitor combination at  will be

In the circuit shown in the figure, the current source I = 1A, voltage source V = 5V, , ,

In steady state, the currents (in A) through R3 and the voltage source V respectively will be

In Figure, the initial capacitor voltage is zero. The switch is closed at t = 0. The final steady-state voltage across the capacitor is:

The circuit shown in Figure is in steady state, when the switch is closed at t = 0.  Assuming that the inductance is ideal, the current through the inductor at equals

A coil of inductance 10H resistance is connected as shown in figure. After the switch S has been in connected with point 1 for a very long time, it is moved to point 2 at t=0

If, at t = 0+, the voltage across the coil is 120V, the value of resistance R is:

The RMS value of the resultant current in a wire which carries a dc current of 10 A and a sinusoidal alternating current of peak value 20 A is

In the circuit shown in Figure, the switch is closed at time t = 0. The steady state value of the voltage is

In the circuit shown in figure, it is desired to have a constant direct current i(t) through the ideal inductor L. the nature of the voltage source v(t) must be:

In the series RC circuit shown in figure the voltage across C starts increasing when the d.c. source is switched on. The rate of increase of voltage across C at the instant just after the switch is closed
(i.e., at ), will be

The time constant of the network shown in figure, is

Two coils having equal resistance but different inductances are connected in series.

The time-constant of the series combination is:  

The switch S in figure is closed at t=0. If  and  respectively, voltages across the capacitors in steady state will be :