Login to track your progress, bookmark questions, and view history.
Practice over 1000+ GATE-level questions from this topic!
Designed to match the latest GATE pattern with topic-wise precision, difficulty tagging, and detailed solutions.
Q#1
Sinusoidal Steady State Analysis
GATE EE 1994
MCQ
+1 mark
-0.33 marks
At resonance, the given parallel circuit constituted by an iron-coil and a capacitor behaves like
An open-circuit
A short-circuit
A pure resistor of value R
A pure resistor of value much higher than R
Explanation:
The phasor diagram for the given circuit is shown below,
At resonance, only in phase component of current remains so that power factor should be unity.
Hence, quadrature component of current must cancel out. 
Total Current, 
is the impedance angle of ‘R - L’ branch.
The current in RL branch would be,
Since 
Total impedance
Since, the power factor is unity the impedance will be resistive.
Login to keep track of your progress with the tool with daily goals, questions preparation and more.
Browse Practice Questions by Chapters / Topics in Browse Practice Questions by Chapters / Topics in GATE Electrical Engineering
Total Questions
Attempted
% Attempted
Correct
% Correct
Login to keep track of your progress with the tool with daily goals, questions preparation and more.
Login to track your progress, bookmark questions, and view history.