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Q#1
Transient Analysis
GATE EE 2003
MCQ
+2 marks
-0.66 marks
In the circuit shown in Figure, the switch S is closed at time t = 0. The voltage across the inductance at 
, is
2V
4V
−6V
8V
Explanation:
Before t=0
Circuit was not energized
So 
and 
Since current through inductor and voltage across capacitor doesn’t change abruptly
and 
i.e., Inductor will behave as open circuit and capacitor will behaves as short circuit
At 
Current from source at , 
Voltage across inductor at 
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