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For the circuit shown in figure. The Norton equivalent source current value is _________ A and its resistance is _________ Ohms
\(I_N = 4A \ and \ R_N = 4.5\Omega\)
\(I_{N} = 2A \ and \ R_{N} = 5.5\Omega\)
\(I_N = 2A \ and \ R_N = 4.5\Omega\)
\(I_N = 1A \ and \ R_N = 4.5\Omega\)
For 
: open circuiting the current source and short circuiting the voltage source. The circuit then is shown below,
To determine IN short circuit the terminals AB and apply source transformation we get the circuit as shown below.
Applying KVL in loop 1
--------------(1)
Applying KVL in loop 2
--------------(2)
Solving equation 1 & 2
Hence, 
and 