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Q#1
BJT
GATE EE 2023
NAT
+2 marks
-0 marks
The Zener diode in circuit has a breakdown voltage of 
. The current gain 
of the transistor in the active region in 99. Ignore base-emitter voltage drop 
. The current through the 20Ω resistance in milliamperes is _________ (Round off to 2 decimal places).
Explanation:
Apply OC Test on Zener diode
Given VBE = 0
25 – 7000 IB – 0 – 10IE – 20IE = 0
25 = 100 IE ∴IE = 0.25A = 250 mA
By KVL: -VD – 0 – IE × 10 = 0
VD = -2.5 V
Zener diode is reverse biased but does not operate in breakdown region & hence open.
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